VerbalExpressions/DartVerbalExpressions

Name: DartVerbalExpressions

Owner: VerbalExpressions

Description: Dart Regular expressions made easy.

Created: 2016-01-05 21:30:10.0

Updated: 2018-03-03 04:54:25.0

Pushed: 2017-01-14 12:11:13.0

Homepage: null

Size: 84

Language: Dart

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README

verbal_expressions

A library for Dart developers that helps to construct difficult regular expressions.

Dart package info is here: https://pub.dartlang.org/packages/verbal_expressions

Quick start

r regex = new VerbalExpression()
.startOfLine()
.then("http").maybe("s")
.then("://")
.maybe("www.").anythingBut(" ")
.endOfLine();

 Create an example URL
ring url = "https://www.google.com";

 Use VerbalExpression's hasMatch() method to test if the entire string matches the regex
gex.hasMatch(url); //True

gex.toString();   // Outputs the regex used: ^http(s)?\\:\\/\\/(www\\.)?([^\\ ]*)\$

art
r regex = new VerbalExpression()..startOfLine()..then("abc")..or("def");

r testString = "defzzz";
Use VerbalExpression's hasMatch() method to test if parts if the string match the regex
gex.hasMatch(testString);   // true

Feel free to use any predefined char groups:

r regex = new VerbalExpression()
  ..wordChar()..nonWordChar()
  ..space()..nonSpace()
  ..digit()..nonDigit();

Define captures:

r expression = new VerbalExpression()
.find("a")
.beginCapture()..find("b")..anything()..endCapture()
.then("cd");

gExp regex = expression.toRegExp();

r match = regex.firstMatch(text);
int(match.group(0)); // returns "abcd"
int(match.group(1)); // returns "b"

Examples

More examples are in example file

Features and bugs

Please find feature requests and bugs at the issue tracker.

Other implementations

You can view all implementations on VerbalExpressions.github.io

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